X^2-24x+140=O

Solution for X^2-24x+140=O equation:

X^2-24X+140=

We move all terms to the left:

X^2-24X+140-()=0

We add all the numbers together, and all the variables

X^2-24X=0

a = 1; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·1·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*1}=\frac{48}{2}
=24
$